5x^2+10x-36x=+36

Solution for 5x^2+10x-36x=+36 equation:

5x^2+10x-36x=+36

We move all terms to the left:

5x^2+10x-36x-(+36)=0

We add all the numbers together, and all the variables

5x^2+10x-36x-36=0

We add all the numbers together, and all the variables

5x^2-26x-36=0

a = 5; b = -26; c = -36;
Δ = b2-4ac
Δ = -262-4·5·(-36)
Δ = 1396
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1396}=\sqrt{4*349}=\sqrt{4}*\sqrt{349}=2\sqrt{349}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{349}}{2*5}=\frac{26-2\sqrt{349}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{349}}{2*5}=\frac{26+2\sqrt{349}}{10}
$